Mean Deviation Calculator

Calculate mean absolute deviation (MAD) from mean or median with step-by-step solution, deviation table, and distribution histogram. Compare MAD vs standard deviation. Free statistics tool.

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8 valid numbers detected
Mean Absolute Deviation (from Mean)
2.0000
8 values
Mean: 5.50
Range: 7

Dispersion Measures Comparison

All spread measures for your dataset side by side

MAD from Mean
2
MAD from Median
2
Std Dev (σ)
2.2913
Variance (σ²)
5.2500
Mean (x̄)
5.5000
Median
5.5000
Range
7
IQR (Q3 − Q1)
3.5000
Q1 (25th %ile)
3.7500
Q3 (75th %ile)
7.2500
Coeff. of Dispersion
36.36%
Count (n)
8

Step-by-Step Calculation

How the mean absolute deviation from the mean is computed

Formula

MAD = ( Σ|xᵢ − | ) / n

Step 1: Calculate the mean

x̄ = (2 + 3 + 4 + 5 + 6 + 7 + 8 + 9) / 8 = 5.5000

Step 2: Find each absolute deviation from the mean

|45.50| = 1.5000

|85.50| = 2.5000

|65.50| = 0.5000

|55.50| = 0.5000

|35.50| = 2.5000

|75.50| = 1.5000

... 2 more values

Step 3: Sum the absolute deviations

Σ|xᵢ − | = 16

Step 4: Divide by the number of values

MAD = 16 / 8 = 2

Interpretation: On average, each data point deviates from the mean by 2 units.

Value Distribution

Frequency distribution of your dataset

1
1
1
1
1
1
1
1
2
3
4
5
6
7
8
9
Mean: 5.5000
MAD: ±2

Individual Deviations

Absolute deviation of each value from the mean

Value (xᵢ)xᵢ − |xᵢ − |
4-1.50001.5000
8+2.50002.5000
6+0.50000.5000
5-0.50000.5000
3-2.50002.5000
7+1.50001.5000
2-3.50003.5000
9+3.50003.5000
Sum16
MAD÷ 82

Values with |deviation| > 2 × MAD are highlighted as potential outliers.

What Is Mean Deviation?

Understanding average absolute deviation

Mean deviation (also called mean absolute deviation or MAD) measures how spread out values are from a central point — typically the mean or the median. Unlike standard deviation, which squares differences, mean deviation uses absolute values, making it easier to interpret: it tells you the average distance each data point sits from the center.

Mean Absolute Deviation Formula

MAD = ( Σ|xᵢ − x̄| ) / n

Where xᵢ represents each value, x̄ is the mean (or median), n is the number of values, and |...| denotes the absolute value. The result is always non-negative and is expressed in the same units as the original data.

MAD from Mean vs MAD from Median

Two ways to measure mean deviation

MAD from Mean

Calculates the average absolute distance of each data point from the arithmetic mean. This is the most commonly used version and works well when data is roughly symmetric with no extreme outliers.

MAD = Σ|xᵢ − x̄| / n

MAD from Median

Calculates the average absolute distance from the median. The median minimizes the sum of absolute deviations, so this version is always less than or equal to MAD from the mean. It is more robust to outliers and better suited for skewed distributions.

MAD = Σ|xᵢ − M| / n

MAD vs Standard Deviation vs IQR

Comparing measures of spread

Mean Deviation (MAD)

Uses absolute differences. Easier to understand since it stays in the original units. Less sensitive to outliers than standard deviation. Best when you need an intuitive measure of average spread.

Standard Deviation (σ)

Uses squared differences. Amplifies the effect of outliers. Preferred in formal statistics because of its mathematical properties (variance is additive for independent variables).

Interquartile Range (IQR)

The range of the middle 50% of data (Q3 − Q1). Completely ignores outliers. Best for skewed data or when extreme values should have no influence on the measure of spread.

Worked Example

Step-by-step: Dataset 3, 6, 6, 7, 8, 11, 15, 16

Find the mean absolute deviation of: 3, 6, 6, 7, 8, 11, 15, 16

Step-by-Step (from Mean)

  • Mean: (3+6+6+7+8+11+15+16) / 8 = 9
  • |3−9| = 6, |6−9| = 3, |6−9| = 3
  • |7−9| = 2, |8−9| = 1, |11−9| = 2
  • |15−9| = 6, |16−9| = 7
  • Sum = 6+3+3+2+1+2+6+7 = 30
  • MAD = 30 / 8 = 3.75

Results

  • MAD from Mean: 3.75
  • MAD from Median: 3.5
  • Mean: 9
  • Median: 7.5
  • Std Dev (σ): ≈ 4.30
  • Range: 16 − 3 = 13

The MAD of 3.75 tells us that on average, each value in this dataset is 3.75 units away from the mean. Notice that the standard deviation (4.30) is higher because squaring amplifies the larger deviations from 15 and 16.

Frequently Asked Questions

Common questions about mean deviation, absolute deviation, and dispersion measures

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Last updated Apr 28, 2026